#987. The biggest

when green flag clicked
delete all of [numbers v]
add [35] to [numbers v]
add [18] to [numbers v]
add [69] to [numbers v]
add [95] to [numbers v]
add [91] to [numbers v]
add [56] to [numbers v]
set [biggest v] to (item (1) of [numbers v])
set [i v] to (2)
repeat ((length of [numbers v]) - (1))
if <(item (i) of [numbers v]) > (biggest)> then
set [biggest v] to (item (i) of [numbers v])
end
change [i v] by (1)
end
say (biggest)

numbers = []

# When the green flag is clicked
numbers.clear()
numbers.append(35)
numbers.append(18)
numbers.append(69)
numbers.append(95)
numbers.append(91)
numbers.append(56)
biggest = numbers[0]
i = 2
for _ in range(len(numbers) - 1):
    if numbers[i - 1] > biggest:
        biggest = numbers[i - 1]
    i += 1
print(biggest)

let biggest = 0, i = 0;
const numbers = [];

// When the green flag is clicked
numbers.length = 0;
numbers.push(35);
numbers.push(18);
numbers.push(69);
numbers.push(95);
numbers.push(91);
numbers.push(56);
biggest = numbers[0];
i = 2;
for (let j = 0; j < numbers.length - 1; j++) {
  if (numbers[i - 1] > biggest) {
    biggest = numbers[i - 1];
  }
  i += 1;
}
console.log(biggest);

💡 Not sure? Build it in Scratch and try it out.